7:47 PM ....o Sprint F usu34ny.theexpertta.com C Homewol rk, Ch.22 Begin Date: 3

Question

7:47 PM ....o Sprint F usu34ny.theexpertta.com C Homewol rk, Ch.22 Begin Date: 3/14/2017 12:00:00 AM Due Date 3/25/2017 2:00:00 AM End Date 3/25/2017 12:00:00 AM perpendicular to the Earth's field analitude whete the field streng is liD 25% Part (a) What will the speed of the proton be in m/s? 25% Part (b) What would the radius of the path be in meters if the proton had the same speed as the electron? 25% Part (c) What would the radius be in meters if the proton had the same kinetic energy as the electron? a 25% Part (d) What would the radius be in meters if the proton had the same momentum as the electro All costante 2017 Expert TALLC

Explanation / Answer

(a)

Here,

magnetic force = centripetel force

B*q*v = m*v^2 / r

R = m*v / q*B

R = 9.1*10^(-31)*7.5*10^6 / 1.6*10^(-19)*1*10^(-5)

R = 4.26 m

speed of proton,

v = B*q*R / m

v = 1*10^(-5)*1.6*10^(-19)*4.26 / 1.67*10^(-27)

v = 4.08*10^3 m/s

(b)

R = mv / qB = 1.67*10^(-27)*7.5*10^6 / 1.6*10^(-19)*10^(-5)

R = 7.82 m

(c)

As given that,

Ke = Kp

(1/2)*me*ve^2 = (1/2)*mp*vp^2

vp = sqrt(me /mp)*ve

R = mp*vp / q*B = sqrt(me*mp)*ve / q*B

R = sqrt(9.1*10^(-31)*1.67*10^(-27))*7.5*10^6 / 1.6*10^(-19)*10^(-5)

R = 182.76 m

(d)

me*ve = mp*vp

R = mp*vp / q*B = me*ve / q*B

R = 9.1*10^(-31)*7.5*10^6 / 1.6*10^(-19)*10^(-5)

R = 4.26 m

answer

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