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Edit View History Bookmarks People Window Help Sun Mar 26 5.11:05 PM MasteringPhysics: Ch 12 HW Secure https://session.masteringphysics.com/myct/itemView?assignmentProblemID 73337563 Signed in as lsaiah Alexander Help Close PHY143 W17 College Physics Tarini Ch 12 HW Introduction to the Ideal Gas Law previous 2 of 10 l next Introduction to the Ideal Gas Law Part A sample enclosed in a rigid metal container at room temperature (20.00 has an absolute A gas pressure pi.The container is immersed in hot water until it warms to 40.0°C. What is the new absolute Learning Goal: pressure p? To understand the ideal gas law and be able to apply it to a wide variety of situations. Express your answer in terms of pi. The absolute temperature T, volume V. and pressure p of a gas sample are related by the ideal gas law, which states that 1.068 Here n is the number of moles in the gas sample and R is a gas constant that applies to all gases. This empirical law describes gases well only if they Hints My Answers Give Up Review Part are sufficiently dilute and at a sufficiently high temperature that they are not on the verge of condensing. incorrect: Try Again: 5 attempts remaining In applying the ideal gas law, p must be the absolute pressure, measured with respect to vacuum and not with respect to atmospheric pressure, and T must be the absolute temperature, Part B measured in kelvins (that is, with respect to absolute zero, defined as p pascals and Vis in cubic This question wil be shown after you complete previous question(s). meters, use R 8.3145 J/(mol. K). p is in atmospheres and Vis in liters, use R 0.08206 L atm/(mol K) instead. Part C This question will be shown after you complete previous question(s) Daniel W BA/MD program NJL.

Explanation / Answer

We know that

using the gas equation

P V = n R T

P1 V = n R ( 20+273.15 )

P2 V = n R ( 40 + 273.15 )

P1 V = n R ( 293.15 ) ------(1)

P2 V = n R ( 313.15 )-------(2)

by considering equation ----(1)

P1 / ( 293.15 ) = n R / V

we have from equation -----(2)

P2 = n R / V ( 313.15 )

then by substituting

P2 = P1( 313.15 ) / ( 293.15 )

P2 = 1.068224 P1

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