(8%) Problem 12: Consider the compound optical system shown in the diagram, wher

Question

(8%) Problem 12: Consider the compound optical system shown in the diagram, where two thin lenses of focal lengths 65 cm (left lens and 36.5 cm (right lens are separated by a distance 25 cm. Otheexpertta.com 13% Part (a) If an object is placed a distance do >fi to the left of the first lens (the left lens), will the resulting image from the first lens be real or virtual, and inverted or upright? 13 Part (b) If a 2.9 cm tall object is placed as indicated in part (a), and the image formed is 0.64 cm tall, what is the magnification of the first lens? 13% Part (c) Using the information from part (b), calculate the image distance, in centimeters, from the first lens Grade Summary dil 18.85 Deductions 0% 100% Potential 8 9 HOME tan0 cos() Sin Submissions Attempts remaining: 14 cotan0 asin acos0 4 5 6 per attempt) atan acotan0 sinh0 detailed view cosh0 tanh0 cotanh0 END Degrees Radians vo BACKSPACE DEL CLEAR Submit Hints 5% deduction per hint. Hints remaining 2 Feedback 5% deduction per feedback. 13% Part (d) Does the image formed by the first lens serve as a real or a virtual object for the second lens? A 13% Part (e) What is the image distance, in centimeters, for the second lens? A 13% Part (f What is the magnification of the second lens A 13% Part (g) What is the total magnification of this compound optical system? 13 Part (h) Is the image created by the second lens real or virtual? Is it upright or inverted?

Explanation / Answer

Given that f1 = 6.5 cm and f2 = 36.5 cm

d = 25 cm

a) if do > f1,then the formed image is real and inverted

b) magnification is m1 = -hi/ho = -0.64/2.9 = -0.22

take positive sign m1 = 0.22

C) for first lens

1/f1 = 1/do + 1/di

1/6.5 = (1/do)+(1/di)

m1 = -di/do = hi/ho

-di/do = -0.22

do = di/0.22

then

1/f1 = (0.22/di) + (1/di)

1/6.5 = (0.22/di)+(1/di)

di = 7.93 cm

d) Virtual object for second lens

e) object distance for second lens is do'= 25-7.93 = 17.07 cm

f2 = 36.5 cm

1/f2 = (1/do') + (1/di')

1/36.5 = (1/17.07)+(1/di')

di' = -32.06 cm

f) magnification is m2 = -di'/do' = 32.06/17.07 = 1.87

g) total magnification is M = m1*m2 = 0.22*1.87

M = 0.42

h) image formed by the second lens is virtual and upright

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.