A solid, homogeneous sphere with a mass of m_0, a radius of r_0 and a density of

Question

A solid, homogeneous sphere with a mass of m_0, a radius of r_0 and a density of rho_0 is placed in a container of water. Initially the sphere floats and the water level is marked on the side of the container. What happens to the water level, when the original sphere is replaced with a new sphere which has different physical parameters? Notation: r means the water level rises in the container, f means falls, s means stays the same. Combination answers like 'f or s' are possible answers in some of the cases. The new sphere has a density of rho > rho_0 and a radius of r = r_0. The new sphere has a mass of m

Explanation / Answer

(a) Sphere will fall due to high density (f)

(b) Sphere will rises as its mass reduced (r)

(c) Sphere will fall because as radius decreases but mass remains same hence density increases (f)

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