Suppose that the rod in Fig. 22–12 moves to the left, so that the area enclosed

Question

Suppose that the rod in Fig. 22–12 moves to the left, so that the area enclosed by the conducting path decreases at the rate of 1.0 103 cm2/s. Find the magnitude and direction of the current if the resistance of the conduct- ing path is 0.10 and the magnetic field strength is 0.50 T. ***Please show work and include any additional drawings if helpful. Thank you for your help!

Explanation / Answer

e = -dphi/dt

phi = B*A

e = -d(BA)/dt

dA/dt = 1 x 10^3 cm^2/s = 1 x 10^3 x 10^-4 m^2/s = -0.1 m^2/s

B = 0.50 T

e = 0.50 * 0.1 = 0.05 V

I = e/R = 0.05/0.10 = 0.5 A

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