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The heaviest invertebrate is the giant squid, which is estimated to have a weigh

ID: 1551874 • Letter: T

Question

The heaviest invertebrate is the giant squid, which is estimated to have a weight of about 0.29 tons spread out over its length of 37 feet. What is its weight in newtons? N A football punter accelerates a football from rest to a speed of 12 m/s during the time in which his toe is in contact with the ball (about 0.26 s). If the football has a mass of 0.43 kg, what average force does the punter exert on the ball? N A bag of sugar weighs 1.00 lb on Earth. What would it weigh in newtons on the Moon, where the free-fall acceleration is one that on Earth? N Repeat for Mercury, where g is 0.367 times that on Earth. N Find the mass of the bag of sugar in kilograms at each of the three locations. Earth kg Moon kg Mercury kg A freight train has a mass of 1.3 times 10^7 kg. If the locomotive can exert a constant pull of 7.0 times 10^5 N, how long does it take to increase the speed of the train from rest to 78 km/h? min A 65-kg man standing on a scale in an elevator notes that as the elevator rises, the scale reads 837 N. What is the acceleration of the elevator? m/s^2 upward

Explanation / Answer

here,

Ques 1:

mass of squid, m = 0.29 tons = 263.084 kg

weight of squid, w = m * g

weight of squid, w = 263.084 * 9.81

weight of squid, w = 2580.854 N

Ques 2:

velocity, v = 12 m/s

time, t = 0.26 s

Force, F = mass * velocity/time

Force, F = 0.43 * 12/0.26

Force, F = 19.85 N

Ques 3:

mass of sugar on earth, m = 1 * 0.453 = 0.453 kg

weight of sugar on moon, wmoon = 0.453 * (9.81/6)
weight of sugar on moon, wmoon = 0.741 N

weight of sugar on mercury, wmercury = 0.453 * (9.81*0.367)
weight of sugar on mercury, wmercury = 1.631 N

mass remain same at all location but acceleration due to gravity varies

Ques 4:

mass of train, m = 1.3*10^7 kg

pulling force, fl = 7*10^5 N

velocity, v = 78 km/hr = 78 * 1000 / 3600 = 21.667 m/s

Force = mass * velocity / time

time, t = mass * velocity/force

time, t = 1.3*10^7 * 21.667/(7*10^5)

time, t = 402.387 s

time, t = 6.706 min