The light bulb in the circuit diagram of the figure has a resistance of 1.1 ohms

Question

The light bulb in the circuit diagram of the figure has a resistance of 1.1 ohms. Consider the potential difference between pairs of points in the figure. Suppose that E=4.0V.   a) What is the magnitude of V12 ?      b) What is the magnitude of V23 ?   c) What is the magnitude of V34 ?   d)   What is the magnitude of V12 if the bulb is removed from the socket? e) What is the magnitude of V23 if the bulb is removed form the socket?    f) What is the magnitude of V34 if the bulb is removed form the socket?

please explain and show all steps!!!

Explanation / Answer

E = 4.0 V

Rb = 1.1 ohm

R = 2 ohm

I = E / (Rb + R) = 4/3.1 = 1.290 A

a)

V12 = 2*1.29 = 2.58 V

b)

V23 = 1.1*1.29 = 1.42 V

c)

V23 = 0*1.29 = 0 V

d)

V12 = 2*0 = 0 V

e)

V23 = E - V12 = 4 - 0 = 4.0 V

f)

V34 = 0*0 = 0 V

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