5%Problem 10: A negative charge of qE-EX10 and m 10 kg enters a magnetic field B

Question

5%Problem 10: A negative charge of qE-EX10 and m 10 kg enters a magnetic field B 1AT with initial velocity v 560 m/s, as shown in the figure. The magnetic field points into the screen. X X X X X X X Randomized Variables X X X X X X X 7.9 x 10 17c m m 1.1 x 10 26 kg X X X X X X X B m 1AT v 560 m/s X X X X X X X Otheexpertta.com D 13% Part (a) Which direction will the magnetic force be on the charge? Grade Summary Into the screen. To the right Down out of the screen. To the left Potential 100% Submit I give up! Attempts remaining: Hints deduction per hint Hints remaining .L Feedback dedaction per feedback. per attempt) detailed view ie 13% Part (b) Express the magnitude of the magnetic force, F.in terms of q, B. 13% Part (c) Calculate the magnitude of the force F, in newtons. 13% Part (d Under such a magnetic force, which kind of motion will the charge undergo? i A 13% Part (e) Express the centripetal acceleration of the particle in terms of the force F and the mass m. i A 13% Part (n calculate the magnitude of a, in meters per square second. 13% Part (g Express the radius, R, of the circular motion in terms of the centripetal acceleration a and the speed v. ial A 13% Part Cha) Calculate the numerical value of the radius R. in meters

Explanation / Answer

Here ,
part a )

Using right hand rule

the direction of magnetic field = q * V X B

direction of magnetic field = downwards

part B)

magnitude of magnetic force = v * q * B

c)

magnitude of magnetic force = 7.9 *10^-17 * 1.4 * 560

magnitude of magnetic force = 6.19 *10^-14 N

d)

the motion will be uniform circular motion

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