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Question

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How far does m travel downward between 0.390 s and 0.590 s after the motion begins?
5.36×10-1 m

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(C) The cylinder is changed to one with the same mass and radius, but a different moment of inertia. Starting from rest, the mass now moves a distance 0.409 m in a time of 0.450 s. Find Icm of the new cylinder.

Explanation / Answer

c)

from

S=Vot+(1/2)at2

0.409=0+(1/2)*a*0.452

a=4.04 m/s2

mg-Icma/r2=ma

Icm=m(g-a)*r2/a =0.85*(9.81-4.04)*0.1272/4.04

Icm=0.0196 Kg-m2

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