I can\'t figure out all parts, need help (11%) Problem 11: An infinitely long si
ID: 1553483 • Letter: I
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I can't figure out all parts, need help
(11%) Problem 11: An infinitely long single wire with current 7.5 A and a rectangle wire loop with current I2 0.15 A are in the same plane as shown. The dimensions of the loop are a 0.027 m and b 0.065 m. The infinite wire is parallel to side AD of the loop and at a distance d 0.22 m from it. com A 13% Part (a) Express the magnitude of the magnetic force Fad, from 11 on wire AD in terms of II, I2, d and the loop dimensions Grade Summary Fad 0% Deductions Potential 100% 7 8 9 Submissions Attempts remaining: 4 5 6 (19 per attempt) 2 3 detailed view m P t BACKSPACE LCI CAR eedbaek Submit Hint I give up! Hints: deduction per hint. Hints remaining Feedback 0% deduction per feedback. Submission History Answer Hints Feedback Totals 09% Totals 0% A 13% Part (b) Calculate the numerical value of Fad in N A 13% Part (c) Express the magnitude of the magnetic force Fbc, from 1 on wire BC in terms of II, I2, a, b, and d A 13% Part (d) Calculate the numerical value of Fbc in N A 13% Part (e) Is the force of Fad repulsive or attractive? A 13% Part (f Is the force of Fbc repulsive or attractive? A 13% Part (g The forces of Fad and Fbc both act on the infinite wire Il. Do they sum to produce a net attractive or repulsive force A 13% Part (h) Calculate the numerical value of the sum of the forces F Fad Fbc on the infinite wire in NExplanation / Answer
field at a distance d from I1 is B1 = mu_o*I1/(2*pi*d)
Force Fad = B1*I2*b
then Fad = mu_0*I1*I2*b/(2*pi*d)
b) Fad = (4*3.142*10^-7*7.5*0.15*0.065)/(2*3.142*0.22) = 6.64*10^-8 N
C) FBC= B1*I2*L
B1 = mu_o*I1/(2*pi*(d+a))
FBC = mu_o*I1*I2*b/(2*pi*(d+a))
D) FBC = (4*3.142*10^-7*7.5*0.15*(0.065)/(2*3.142*(0.22+0.027)) = 5.92*10^-8 N
E) into AD ,the currents I1 and I2 are in same directions,then Force on AD is attractive
F) into BC ,the currents I1 and I2 are in opposite directions,then then the Force on BC is repulsive
g) since Fad > Fbc,so they sum produce a net attractive
h) F = Fad-Fbc = (6.64-5.92)*10^-8 = 7.2*10^-9 N
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