(7%) Problem 8: The Seawolf class nuclear submarines have a crush depth of appro
ID: 1553799 • Letter: #
Question
(7%) Problem 8: The Seawolf class nuclear submarines have a crush depth of approximately d 750 m. The density of seawater is o 03x105 kg/m Atmospheric pressure is Po 1.01x105 Pa. Otheexpertta.com A 50% Part (a) Find the inward force of the water, in newtons, at crush depth on a circular porthole with a radius of r 0.24 m. Grade Summary Deductions 0% Potential 100% sino coso tano 7 8 9 Submissions Attempts remaining 6 4 5 6 cotan() asin() acos() (09 per attempt) 1 2 3 detailed view atan acotano sin cosh() tanh 0 cotanh0 o Degrees Radians Hint I give up! Hints 0% deduction per hint. Hints remaining 2 Feedback 0% deduction per feedback. A 50% Part (b) If the interior of the submarine is kept at atmospheric pressure, what will be the magnitude of the net force on the porthole in newtons?Explanation / Answer
Given
d = 750 m, density of sea water is rho = 1.03*10^3 kg/m3
and atmospheric pressure is P0 = 1.01*10^5 Pa
PArt (a)
radius of porthole is r = 0.24 m
area of the porthole is A = pi*r^2 = pi*0.24^2 = 0.181 m2
the pressure at d is P = rho*g*h = 1.03*10^3*9.8*750 Pa = 7570500 Pa
the force is F = P*A = 7570500*0.181 N = 1370260.5 N
PArt B
given pressure is P = 1.01*10^5 Pa
force F = P*A = 1.01*10^5 *0.181 N = 18281 N
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