Light passes through two polarizers. The intensity of the light emerging from th

Question

Light passes through two polarizers. The intensity of the light emerging from the second polarizer is 29.0% of the intensity of the light that is incident on the first polarizer. In both cases below, the angle you state should be a positive value between 0 degrees and 90 degrees.

(a) If the incident light is unpolarized, what is the angle between the transmission axes of the two polarizers?

(b) Now, you replace the unpolarized incident light by polarized incident light of the same intensity. Once again, the intensity of the light emerging from the second polarizer happens to be exactly the same as that obtained with the unpolarized light. What is the angle between the polarization direction of the incident light and the transmission axis of the first polarizer?

Light passes through two polarizers. The intensity of the light emerging from the second polarizer is 29.0% of the intensity of the light that is incident on the first polarizer. In both cases below, the angle you state should be a positive value between 0 degrees and 90 degrees. (a) If the incident light is unpolarized, what is the angle between the transmission axes of the two polarizers? 70.5 (b) Now, you replace the unpolarized incident light by polarized incident light of the same intensity. Once again, the intensity of the light emerging from the second polarizer happens to be exactly the same as that obtained with the unpolarized light. What is the angle between the polarization direction of the incident light and the transmission axis of the first polarizer?

Explanation / Answer

here,

a)

let the intensity of light incident on first polarizer be I0

when it passes through the first polarizer , I1 = I0/2

let the angle between the axis of frist and seccond polarizer be theta

when it passes throught the seccond polarizer

I2 = I1 * cos^2(theta)

0.29 * I0 = 0.5 * I0 * cos^2(theta)

theta = 40.4 degree

b)

let the angle between the polarization direction of the incident light and the transmission axis of the first polarizer be phi

0.5 * I0 = I0 * cos^2(phi)

phi = 45 degree

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