A diagram for a compound microscope is shown below (from Physics by Douglas C. G

Question

A diagram for a compound microscope is shown below (from Physics by Douglas C.

Giancoli). Using the two lenses you used in the lab, suggest the design of the compound

microscope (which lens would you use as an objective, and which as an eyepiece, and

how far apart?) and determine its magnification as M = (l – f e )/d o .

diagram, characterize the image, and determine the magnification M. 5. A diagram for a compound microscope is shown below (from Physics by Douglas C Giancoli. Using the two lenses you used in the lab, suggest the design of the compound microscope (which lens would you use as an objective, and which as an eyepiece, and how far apart?) and determine its magnification as M (l f)/d, Object Eyepiece Objective Page 3 3

Explanation / Answer

Solution:

A compound microscope consists of two convex lenses , one is an objective lens , the other is an eye piece.

Objective lens is a Convex lens of small aperture and Small focal length. It is directed towards the object which has to be magnified.

Eye piece is also a convex lens of larger aperture and of Large Focal length , and is used to observe the magnified image .

The distance between the objective and the eye piece is equal to the Least distance of distinct vision (Near point ) of the eye L.

b) Magnifying power of a compound microscope = M = mo * me

mo = magnification produced by the objective = (di / do ) where di = image distance of objective

do = object distance of the objective .

Let the final image be formed at the near point . Let L be the distance between the objective and eye piece.

Since the image formed finally is a virtual image , magnication = M = (di / do) (D/fe)

when do = approximately fo , i.e., the object is adjusted to be at the focal point of the objective ,

and distance between the two lenses = L = di + doe where doe is the object distance for the eye piece. and di = image distance of objective. and do = approx . fo

So do = image distance of objective = L - fe

Using M = ( di/do ) ( D/fe) = [(L - fe) /do ][D/fe] = approximately ( L - fe) /do ,when D/fe = 1

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