Potentiometers are used to measure the emf provided by a source without affectin
ID: 1554593 • Letter: P
Question
Potentiometers are used to measure the emf provided by a source without affecting the emf by drawing current from the source as a non-ideal voltmeter would. The potentiometer circuit shown below demonstrates how it works. The resistor R is a wire of known length & constant cross section connected to source of known emf. Contact c can be slid along legnth of the wire and conected to unknown source of emf, x. Bottom loop also contains ammeter. Contact c is then moved until ammeter measure 0 current.
a. If curent Ix = 0, what is current through top loop in terms of R and ?
b. Find relationship between x & I.
c. Source of known emf 2 replaces x and slider is moved until current through bottom branch disappears so I2 = 0. What is now the current through top loop?
d. Find a relation between 2 and R2 , the new resistance between point a & c.
e. Using information worked out in part a, b, c show that x = ( Rx / R2 ) 2 .
f. If length ac = 33.6 cm , length ac = 45.8 cm, total length of resistor R = 100 cm, 2 = 1.0182 V, calculate unknown emf.
--- -w 4 60 .1Explanation / Answer
a.) If curent Ix = 0, what is current through top loop in terms of R and ?
since the current Ix = 0, the current through top loop would be I.
Now, I = applying Kirchoff's Voltage Law (KVL) in the top loop we get:
- IR = 0
or I = /R which is current through top loop in terms of R and .
b.) Find relationship between x & I.
Contact c moves along the legnth of the wire until ammeter measure 0 current. At this moment aplying KVL in the lower loop gives
IRx - x = 0 (as Ix = 0)
or x = IRx where Rx is the resistance in the length of the wire where the Contact c shows Ix = 0
(c.)
We apply KVL in the top loop and get:-
= IR
Now, applying KVL in the bottom loop gives
2 = IR2
So I = 2/R2 is the current through top loop
(d.)
From (c) we got
= IR and
2 = IR2
solving these two equations we get
/2 = R/R2
or 2 = (R2)/R ..
feel free to ask if anything is left out by me.......
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