8) A 12 kg block of wood hangs on the end of a 1.5 m long rope. The maximum tens

Question

8) A 12 kg block of wood hangs on the end of a 1.5 m long rope. The maximum tension the rope can withstand is 250 Newtons. A 0.35 kg knife is thrown horizontally into the wooden block, where it embeds itself. What is the maximum speed the knife can have and not break the rope? 8) A 12 kg block of wood hangs on the end of a 1.5 m long rope. The maximum tension the rope can withstand is 250 Newtons. A 0.35 kg knife is thrown horizontally into the wooden block, where it embeds itself. What is the maximum speed the knife can have and not break the rope?

Explanation / Answer

Total force due to block and knife = 250 N for maximum speed and no breaking of rope

force due to block = 12*9.8 =117.6 N

force due to knife = 250-117.6 = 132.4N

ma = 132.4 N

a = 132.4 / 0.35 = 378.29 m/s2

final speed = 0 and inital or maximum speed =u

S =1.5m

a = v2-u2 / 2S

u = (2 * 1.5* 378.29 )0.5 = 33.69m/s

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