History Bookmarks omlibiscms/modWibis/view.php?id 3390903 ity-PHms 211 spring17-

Question

History Bookmarks omlibiscms/modWibis/view.php?id 3390903 ity-PHms 211 spring17-smNNETT I Activities and Due Dates I Hw Momentum Impulse and Collisions Gradebook 4/5/2017 11:00 PM 36.8/100 G 4 1/2017 0200 AM Print Ecalculator Periodic Table Question 6 of 19 Sapling Learning A professional golfer is examining a video of a practice swing, The high-speed footage shows that his club gun clocks the speed of the ball as 191 mph after it comes off the club. The golf ball has a mass of 45.9 grams. What is the magnitude of the impulse imparted to the ball by the club kg m What is the magnitude of the average force of contact between the club and the bal?

Explanation / Answer

Time: t = 0.771 ms = 0.771x10-3 s

speed: v = 191 mph = 191 [1609/3600] = 85.366 m/s

mass: m = 45.9 g = 45.9x10-3 kg

Answer:

impulse: I = m*dv = [45.9x10-3 ]*[85.366 - 0] = 3.9182994 kg.m/s = 3.91 kg.m/s

Force: F = impulse/time = 3.9182994 / 0.771x10-3 = 5082.1 N

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