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CA 90% B Wed 3:09 PM Faha History Bookmarks People window Help com/ibiscms/mod/ibis/view.php?id 3390903 4/5/2017 11:00 PM 368/100 G 4/1/2017 0200 AM Gradebook Me e Print Calculator l Periodic Table Sapling Learning 2.400 mass of the approach each other with equal and opposite speed of one and the particle is nm, where just unitess Snapshots of the system before, After the colision the finst particle moves in the exact opposite direction with speed 240v, and the speed of the second particle is unknown. What is the value of n? Previous Check Answer oNet Exit

Explanation / Answer

assume right side is positive

using linear momentum conservation

mv + nm(-v) = m*-2.4v + nm*v2

v - nv = nv2 - 2.4v

3.4v - nv = nv2

v2 = v(3.4-n)/n

kinetic energy remain conserve in elastic collsion

mv^2/2 + nmv^2/2 = m*(2.4v)^2/2 + nm* (v2)^2/2

v^2 + nv^2 = 5.76v^2 + nv2^2

-4.76v^2 + nv^2 = v^2(3.4-n)^2/n^2

-4.76v^2n^2 + n^3v^2 = 11.56v^2 + n^v^2

solving these equations

v1f = (m -nm)*v/(m+nm) + (2nm)*(-v)/(m+mn)

-2.4 = (m-nm) /(m+nm) - (2nm/m+nm)

-2.4 = (m-3nm)/(m+nm)

n = 5.67 = 5

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