The lower end of the thin uniform rod in (Figure 1) is attached to the floor by
ID: 1555424 • Letter: T
Question
The lower end of the thin uniform rod in (Figure 1) is attached to the floor by a frictionless hinge at point P. The rod has mass 0.0920 kg and length 23.0 cmand is in a uniform magnetic field 0.130 T that is directed into the page. The rod is held at an angle 55.0 above the horizontal by a horizontal string that connects the top of the rod to the wall. The rod carries a current 12.0 A in the direction toward P.
Calculate the tension in the string. Use the fact that =12IBL2 for a uniform bar of length L carring a current I in a magnetic field B.
Express your answer with the appropriate units.
X X X XExplanation / Answer
Tm = 1/2 I B L2
Torque due to gravity Tg = m g * L/2 * cos theta
Torque due to tensio = T L sin theta
Balancing torque's T = IBL + m g cos theta / 2 sin theta
T = ((12 * 0.130 * 23 * 10-2) + (0.092 * 9.8 * cos 55)) / ( 2 * sin 55)
T = 0.535 N
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