UNIVERSITY HAWAII Physics Department Class ID S17-170-H6 Phys 170. General Physi
ID: 1556345 • Letter: U
Question
UNIVERSITY HAWAII Physics Department Class ID S17-170-H6 Phys 170. General Physics I Spring 2017 Prof. Klaus Sattler Signature Due Wednesday April 5. 2017 G An 8.00 kg point mass and a 15.0-kg point mass are held in place 50.o cm apart. A particle of mass m is released from a point between the two masses 20.0 cm from the 8.00-kg mass along the line connecting the two fixed masses. Find the magnitude and direction of the acceleration of the particle. O A sate te with a mass of 300 kg moves in a circular orbit 5 x 10 m above the earth's surface (a) What is the gravitational force on the satellite? (b) What is the speed of the satellite? (c) hat is the period of the satellite? 3. The asteroid Icarus. discovered in 1949. was so named because its highly eccentric elliptical orbit brings it close to the sun at perihelion. The eccentricity e of an ellipse is defined by the relation r a(1-e), where Pr is the perihelion distance and a is the semimajor axis. Icarus has an eccentricity of 0.83 and a period of 1.1 y.(a) Determine the semimajor axis of the orbit of lcarus. (b) Find the perihelion and aphelion distances of the orbit of Icarus. small block is attached to an ideal spring and is moving in simple harmonic motion on a horizontal, frictionless surface. When the amplitude of the motion is 0.090 m, it takes the block 2.70 to travel from x 0.090m to x- 0.090 m. If the amplitude is to x 0.180 m, how long does it take to travel (a) from x 0.180 m to x 0.180 m and (B) from x 0.090 m to x -0.090 m? 50.0-g hard-boiled moves on the end of a spring with force constant k 25 Nm. initial displacement is 0.300 m. A damping force F by, acts on the e Its Calculate theExplanation / Answer
( a )
F = GMm / r2;
F = 6.67 *10 -11 * 6 *1024 * 300 / (5*107 + 6*106 ) 2 ;
F = 38.2844 N
( b )
mv2 / r = GMm / r2 ;
v2 = GM / r ;
v2 = 6.67 *10 -11 * 6 *1024 / [ 5*107 + 6*106 ] ;
v = 2673.2804 m /s
(c )
T = 2 r / v ;
T = 2 * ( 5*107 + 6*106 ) / 2673.2804
T = 131620.45 s ~ 2193.67 min ~ 36.5611 hours ~ 1.523 days
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