MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 28, Problem
ID: 1556843 • Letter: M
Question
MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 28, Problem 32 GO 10 kg, and the An electron is accelerated from rest through a potential difference that has a magnitude of 3.30 x 107 v. The mass of the electron is 9.11 x 31 negative charge of the electron has a magnitude of 1.60 x 10 19 c. (a) what is the relativistic kinetic energy (in joules) of the electron? (b) What is the speed of the electron? Express your answer as a multiple of c, the speed of light in a vacuum. (a) Number Units (b) Number Units GO TUTORIAL SUBMIT ANSWER Question Attempts: Unli Mited SAVE FOR LATER MapleNet copyright o 2000-2017 by John wiley &Sons;, Inc. or related companies ATrights reserved. Version 4.22.2.9 eno Polo I R2000-2017-20bn wley Asens. Inc. All Rights Reserved. A Division of lohn Wley Sons Inc.Explanation / Answer
here,
magnitude of potential difference , V = 3.3 * 10^7 V
a)
the relativistic kinetic energy = work done on electron
KE = V * q
KE = 3.3 * 10^7 * 1.6 * 10^-19 J
KE = 5.28 * 10^-12 J
b)
let the speed of electron be v
KE = m0 * c^2 * ( 1/(sqrt(1- (v/c)^2)) -1)
5.28 * 10^-12 = 9.1 * 10^-31 * (3 * 10^8)^2 * ( 1/sqrt(1 - (v/(3 * 10^8))^2 ) - 1)
solving for v
v = 2.99 * 10^8 m/s
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