A 38.5 kg box initially at rest is pushed 5.80 m along a rough, horizontal floor

Question

A 38.5 kg box initially at rest is pushed 5.80 m along a rough, horizontal floor with a constant applied horizontal force of 145 N. If the coefficient of friction between box and floor is 0.300, find the following. (a) the work done by the applied force J (b) the increase in internal energy in the box-floor system due to friction J (c) the work done by the normal force J (d) the work done by the gravitational force J (e) the change in kinetic energy of the box J (f) the final speed of the box m/s

Explanation / Answer

a] Work done by the applied force = FS = 145(5.80) = 841 J

b] Increase in energy = work done by friction = umgS = 0.3(38.5)(9.8)(5.8) = 656.502 J

c] Work done by Normal force = RScos90 = 0 J

d] Work done by gravity = 0 J

e] change in kinetic energy of the box = Net Work done = 841 - 656.502 = 184.498 J

f] change in kinetic energy = (1/2)m[v2 - u2] = (1/2)m[v2 - 02]

=> v = 3.096 m/s.

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