M1 (0,0) M2 (0.06,0.08) M3 (0.12,0) M1=0.1 m M2=0.2 m M3=0.1 m A) what are the c
ID: 1557980 • Letter: M
Question
M1 (0,0) M2 (0.06,0.08) M3 (0.12,0) M1=0.1 m M2=0.2 m M3=0.1 m A) what are the coordinates of the center of mass B) find the inertia if an axis passes through M2 perpendicular to the page.M1 (0,0) M2 (0.06,0.08) M3 (0.12,0) M1=0.1 m M2=0.2 m M3=0.1 m A) what are the coordinates of the center of mass B) find the inertia if an axis passes through M2 perpendicular to the page.
M2 (0.06,0.08) M3 (0.12,0) M1=0.1 m M2=0.2 m M3=0.1 m A) what are the coordinates of the center of mass B) find the inertia if an axis passes through M2 perpendicular to the page.
Explanation / Answer
xcm = m1x1+m2x2+m3x3/mtot
xcm = 0+0.2m*0.06+0.1m*0.12/0.4m = 0.06
yxm = m1y1+m2y2+m3y3/mtot = 0+0.2m*0.08+0/0.4m = 0.04
when axis passing through the m2
moment of inertia through m2 is zero
I tot = m1r1^2+m2r2^2 = 0.1m*0.06^2+0.1m*0.06^2 = 0.00072m kg m^2
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