0.24-kg stone is held 1.2 m above the top edge of a water well and then dropped

Question

0.24-kg stone is held 1.2 m above the top edge of a water well and then dropped into it. The well has a depth of 4.6 m. (a) Taking y = 0 at the top edge of the well, what is the gravitational potential energy of the stone-Earth system before the J (b) Taking y = 0 at the top edge of the well, what is the gravitational potential energy of the stone-Earth system when it The response you submitted has the wrong sign. J (c) What is the change in gravitational potential energy of the system from release to reaching the bottom of the well? You submitted has the wrong sign, J A daredevil on a motorcycle leaves the end of a ramp with a speed of 35.3 m/s as in the figure below. If his speed is 32.2 m/s when he Ignore friction and air resistance. m

Explanation / Answer

(a) mgh = 0.24*9.8*1.2 = 2.8224

(b) mgh = 0.24*9.8*(-4.6) = -10.8192

(c) change = Final - Initial = -10.8192 - 2.8224 = -13.6416

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