A 0.080-kg block slides from rest down a frictionless track; ignore air resistan

Question

A 0.080-kg block slides from rest down a frictionless track; ignore air resistance. (a) What is its speed at the top of the loop? (b) How far would it compress an ideal, horizontal spring near the end of the track if the spring constant is 0.90 kN/m? A 0.080-kg block slides from rest down a frictionless track; ignore air resistance. (a) What is its speed at the top of the loop? (b) How far would it compress an ideal, horizontal spring near the end of the track if the spring constant is 0.90 kN/m?

Explanation / Answer

a)

since the block slides from rest at top , therefore speed of the loop at the top is zero.

Vtop=0

b)

By conservation of energy

(1/2)mVbot2=mgH

Vbot=sqrt(2gH)=sqrt(2*9.81*2.2)=6.57 m/s

agian applying conservation of energy

(1/2)mVbot2=(1/2)Kx2

0.08*6.572=900*x2

x=6.2 cm

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