In each case below, calculate the image distance and image size from the given v

Question

In each case below, calculate the image distance and image size from the given values of focal length and object distance. Part (a) and (c) use parameter values that are within the range of the animation, and you can use the animation to verify the result of your calculation. Parts (b) and (d) use parameter values outside the animation range. A 5.00 cm high object is located 37 cm in front of a convex lens of focal length 20.0 cm. Image distance 43.5 cm Magnification -1.18 Image size -11.9 cm Your response differs from the correct answer by more than 100%. Image type real Image orientation inverted A 5.00 cm high object is located 37 cm in front of a convex lens of focal length 60.0 cm. Image distance -10.3.604 cm Your response is within 10% of the correct value, This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. Magnification 2.80 cm Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. Image size 28 cm Your response differs from the correct answer by more than 100%. Image type virtual Image orientation upright A 10.0 cm high object is located 37 cm in front of a concave lens of focal length -20.0 cm. Image distance -13 cm Magnification 0.35 Image size ___ cm Image type virtual Image orientation upright A 10.0 cm high object is located 37 cm in front of a concave lens of focal length 60.0 cm. Image distance ___ cm Magnification ___ Image size ____ cm Image type virtual Image orientation upright

Explanation / Answer

From the given question,

a) height of object(ho)=5cm

image size(hi)=hi

object distance(u)=-37cm

focal length(f)=20cm

image distance(v)=v

from the lens formula

1/v - 1/u =1/f

1/v= 1/u+1/f

v=uf/(u+f)=(-37 x 20)/(-37+20)=43.52 cm

magnification=(-v/u)=-43.52/-37=1.18

magnification=hi/ho

1.18=hi/5

hi=5.9cm.

image size is 5.9cm.

image type:real

image orientation: inverted.

(b) height of object(ho)=5cm

image size(hi)=hi

object distance(u)=-37cm

focal length(f)=60cm

image distance(v)=v

from the lens formula

1/v - 1/u =1/f

1/v= 1/u+1/f

v=uf/(u+f)=(-37 x 60)/(-37+60)=-96.52 cm

magnification=(-v/u)=-96.52/-37=2.6

magnification=hi/ho

2.6=hi/5

hi=13cm.

image size is 13cm.

image type:virtual

image orientation: upright

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