Heat energy absorbed by the cold water through contact with the condensed steam.

Question

Heat energy absorbed by the cold water through contact with the condensed steam.

So I have a equation Qw=MwCw(Teq-Tc)

Mass of empty calorimeter (g) 93.653

Mass of calorimeter + water (g) 229.915

Mass of water (g) 136.262

Mass of Calorimeter, thermometer, and water (g) 248.331

Initial water temp (°C) 24.009

Final water temp (°C) 24.023

Mass of calorimeter, thermometer, water, and condensed steam (g) 250.084

Mass of steam (Msteam) 1.753

How do I find out Qw = (cal) The equation is Qw= Mw X Cw X (Teq-Tc)

I know that Mw stands for mass of cold water, the Cw is the specifc heat of water 1.0 cal/gram °C, the Teq is the Equilibrium temperatrue of the mixture subtracted from the Tc which is the initial temperature of cold water.

Thank you for your help.

Can you please help me?

Explanation / Answer

Heat energy absorbed by the cold water

Qw= Mw X Cw X (Teq-Tc)

    =136.262 X10-3X 1 X (24.023 - 24.009)

   = 1.9 cal

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