Switch S in the figure below is closed at time t = 0, to begin chaining an initi

Question

Switch S in the figure below is closed at time t = 0, to begin chaining an initially uncharged capacitor of capacitance C = 13.0 mu F through a resistor of resistance R = 18.0 ohm. At what time is the electric potential across the capacitor equal to that across the resistor? 10 225 ms Did you use the charging or the discharging equation? What is the final potential on the capacitor? In terms of that amount, how much is on the capacitor when the resistor and capacitor match in potential' Do you knew how to take the antifunction of an exponential?

Explanation / Answer

Given that

capacitance C=13*10^-6 F

resistance R=18 ohm

now we time where Vc=Vr

E(1-e^-t/cr)=Ee^-t/cr

1-e^-t/cr=e^-t/cr

1=2e^-t/cr

1/2=e^-t/cr

log[1/2]=-t/cr

0.3010=t/13*10^-6*18

time t=70.4*10^-6 sec

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