A 0.352 m long metal bar is pulled to the left by an applied force F and moves t

Question

A 0.352 m long metal bar is pulled to the left by an applied force F and moves to the left at a constant speed of 5.90 m/s. The bar rides on parallel metal rails connected through a 44.4 resistor, as shown in (Figure 1) , so the apparatus makes a complete circuit. You can ignore the resistance of the bar and rails. The circuit is in a uniform 0.644 T magnetic field that is directed out of the plane of the figure.

A) Is the induced current in the circuit clockwise or counterclockwise?

B) What is the rate at which the applied force is doing work on the bar? Express your answer with the appropriate units.

Explanation / Answer

L = 0.352 m , v =5.9 m/s, R = 44.4 ohms

B = 0.644 T

from faradays law induced emf = V = BvL

(a) V = IR

induced current is along counterclockwise direction

(b) P = V^2/R

P = (BvL)^2/R

P = (0.644*5.9*0.352)^2/44.4

P = 0.0403 W

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.