4:02 PM session mastering physics com c Home wichita edu Pearson\'s MyLab & what

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4:02 PM session mastering physics com c Home wichita edu Pearson's MyLab & what is o Mastering physic. The Freque PHYSICS I 176 1 of 14 Problem 17.6 Enhanced with Hints shows wave on a 1.1 m long string has been sxed at both ends and tightened unwl the that speed is 20 m/s You may with math skills (G may want to review. bead For help want to review you 462 40) Part A what is the frequency? Express your answer with the appropriate units. f. Value Units Hints My Answers Give Up Review Part Continue

Explanation / Answer

on a length of 1.1 m there are 4 loops

so each loop 1.1/4 = 0.275 m

wavelength L = 2* 0.275 = 0.55 m

relation between wavelength and frequemncy is

V = Lf

f = 20/0.55

f = 36.36 Hz

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from the relation between linear mass density (u) and frequency

f = (1/2L) * sqrt(T/u)

f is inverly proportional to sqrt u

f2^2/f1^2 = u1/u2

as u = mass per unit length

mA/me = fe^2/fa^2

ma/me = (639^2/410^2)

ma/me = 2.42

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