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d Chrome File Edit View History Bookmarks People Window Help Mastering Physics: Week 12 Secure Session mastering physics.com/ 7761800 College Physics I Week 12 Problem 13.48 Problem 13.48 Part A A0.302-kg mass is attached to a spring with a force constant of If the mass is displaced 0.250 m from equilibrium and released, what is its speed when it is 0.120 m from equilibrium? 52.7 N/m. m/s Submit My Answers Give Up 37% Wed 7:08 PM a E Help Close previous l 9 of 22 l next Provide Feedback Continue

Explanation / Answer

from the given data

m = 0.302 kg

K = 52.7 N/m

Amplitude, A = 0.25 m

at x = 0.1 2m, v = ?

Apply conservation of energy

(1/2)*k*x^2 + (1/2)*m*v^2 = (1/2)*k*A^2

m*v^2 = k*A^2 - k*x^2

v^2 = (k/m)*(A^2 - x^2)

v = sqrt((k/m)*(A^2 - x^2))

= sqrt( (52.7/0.302)*(0.25^2 - 0.12^2))

= 2.90 m/s

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