Chapter 02, Problem 015 A particle\'s position is given by x 8.00 15.0ot 32, in

Question

Chapter 02, Problem 015 A particle's position is given by x 8.00 15.0ot 32, in which xis in meters and t is in seconds. (a) what is its velodty at t 1 s? (b) Is It moving in the positive or negative direction of xjust then? (c) What is its speed just then? (d) Is the speed Increasing or decreasing just then? grry answering the next two questions without further calculation.) (e) ls there ever an instant when the velocity is zero? If so, give the time t; if not, answer "o". Is there a time after t-3 s when the particle is moving in the negative direction of x? If so, give the time t; if not, answer "0" (a) Number (b) (c) NDmber (d) Units (e) Number Number (f click if you would like to show work for this question Open Show Work LINK TO SAMPLE PROBLEM LINK TO TEXT LINK TO SAMPLE PROBLE MATH HELP MATH HELP MATH HELP line e2000-201zlohn Wiley s sons. Inc. All Rights Reserved A Division of ohn wreyssons. Inc. MacBook Pro

Explanation / Answer

v = dx/dt

x = 8 -15t + 3t^2

v = -15 + 6t

at t = 1

v = -9 m/s

part b )

since v < 0 so moving in negative direction at t =1 s

part c )

speed = |v| = 9 m/s

part d )

speed is increasing going from negative to positive

part e )

Yes , it is going from negative to positve

-15 + 6t = 0

t = 2.5 s

part f )

v = -15 + 6t

after 3 s

v > 0

0

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