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1) A proton is confined within an atomic nucleus of diameter 3.9 fm (1fm=1015m). Part A Estimate the smallest range of speeds you might find for a proton in the nucleus. Use h/2 instead of h/(4) in equation.

2)

A proton is confined within an atomic nucleus of diameter 3.9 fm (1fm=1015m).

Part A

Estimate the smallest range of speeds v0<vp<+v0 you might find for a proton in the nucleus.

Express your answer with the appropriate units.

A proton is confined within an atomic nucleus of diameter 3.9 fm (1fm=1015m).

Part A

Estimate the smallest range of speeds v0<vp<+v0 you might find for a proton in the nucleus.

Express your answer with the appropriate units.

Explanation / Answer

Given that ;

diameter of the nucleus x = 3.9*10^-15 m

According to Heisenberg's uncertainty principle

x*p = h / 4*pi

m**v = h / 4*pi , since p = m*v

h is plank's constant = 6.62*10^-34

m is mass of proton = 1.67*10^-27 kg

substituting the values

1.67*10^-27 *3.9*10^-15 * v =  6.62*10^-34 / (4*pi)

v = 8.088*10^6 m/s

The smallest range of speeds 8.088*10^6 m/s < vp < +8.088*10^6 m/s for a proton in the nucleus.

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