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THIS Two railway trolleys each of total mass 1.00 10^3 kg approach each other on

ID: 1562535 • Letter: T

Question

THIS Two railway trolleys each of total mass 1.00 10^3 kg approach each other on parallel adjacent tracks. Each is travelling at 10.0 m s^-1 as shown. As they pass, a man in trolley 2 heaves a 50.0 kg bag of cement on to trolley 1 by giving it an impulse at right angles to the motion of the trolleys. A second man in trolley 1 heaves it right back on to trolley 2 also by giving it an impulse at right angles to the motion. (a) What is the total momentum of the system before and after the events described? (b) What is the velocity of each trolley just after the bag arrives on trolley 1? (c) What is the final velocity of each trolley? (d) Suppose instead that the bag is projected in such a way that on each occasion its path through the air is at right angles to the tracks. Repeat parts (b) and (c).

Explanation / Answer

Answer:-

Parta) What is the total momentum of the system before and after the events described ?

we know the formula for the momentum p = m*v

so total momentum before event = p1 +p2   

= 1*103 kg* 10 m/s + 1*103 kg* 10 m/s

= 20x103 kg-m/s

now we have to calculate the momentum after event

for trolley -1 when 50 kg bag heaves from trolley-2 p = (50 +1x103 ) *10 = 10.5 x103 kg-m/s

for trolley -2 when 50 kg bag heaves right back from trolley-2 p = (50 +1x103 ) *10 = 10.5 x103 kg-m/s

so total momentum after event is = 21x103 kg-m/s

b ) what is the velocity of each trolley just after the bag on trolley 1?

momentum on trolley 2 after event is =10.5x103 kg-m/s

so velocity v = p/m = 10.5x103 kg-m/s / 1x103 kg = 10.5 m/s

on trolley when 50 kg bag arrived = v = 10.5x103 kg-m/s / 1.05x103 kg = 10 m/s

c) what is the final velocity of each trolley ?

for trolley -2 after event 50 kg bag will be in trolley 2 so mass will be 1.05x103 kg and final momentum p = 10.5x103 kg-m/s

so final velocity v = 10.5x103 / 1.05x103 kg = 10 m/s

for trolley -1 v = v = 10.5x103 / 1.0x103 kg = 10.5 m/s

d) there will be no change in velocity when we project the bag perpendicular track because the motion direction and the rtrack direction . so velocity will be the same.