R The Expert TAIHuman x a Beave surrender-You x (C An uncharged capacitor x C Se

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R The Expert TAIHuman x a Beave surrender-You x (C An uncharged capacitor x C Secure I https://usn26ms.theexpertta.com/common/TakeTutorialAssignment aspx Home I student: hannahsohn@students.belhaven.edu My Account Log out class Management I Help Chapter 23 Begin Date: 3/2017 12:00:00 AM Due Date: 4/23/2017 59:00 PM End Date: 5/9/2017 12:00:00 AM (8%) Problem 5: Consider the circuit diagram depicted in the figure. E1 8 V 0.50 2,50 Assignment Status 1.52 Click here for 0,50 detailed view 45V A 50% Part a) What equation do you get when you apply the loop nule to the loop abcdefgha in terms of the variables in the figure? Problem Status Grade Smmmary 1 Completed Deductions Potential 00% 2 Completed a 7 8 9 3 Completed Submissions 4 Completed Attempts remaining: (60 per attempt 1 3 detailed view 7 Completed 8 Completed Completed Submit Hint 1give 10 Completed Hints: .00 deduction per bint, Hints remaining 2 Feedback: 1 deduction per feedback. 12 50% Part f the current through the top branch is through the bottom, B, in amps 0.22 A. what is the cunrent 13 All content 2007 Expert TA LLC 2:35 PM Ask me an 4/23/2017

Explanation / Answer

Applying krichoff voltage law for first loop (abcdea)

16 - 0.5*I2 - I1*R1 -2.5*I2 =0

I2 = 0.22 A

16 - 0.5*0.22 - I1*R1 - 2.5*0.22 =0 ..(1)

Applying krichoff voltage law for second loop (aefgha)

-I1*R1 +45 - 0.5*I3 -1.5*I3 = 0..(2)

applying kirchoff current law

I1 = I2 +I3

I1 = 0.22+I3 ..(3)

from (1) ,(2) AND (3)

I1 = 15.05 A

I2 = 14.83 A

R1 = 1.02 ohms

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