In the figure, a conducting rod with length L = 35.0 cmmoves in a magnetic field
ID: 1563199 • Letter: I
Question
In the figure, a conducting rod with length L = 35.0 cmmoves in a magnetic field B of magnitude 0.360 Tdirected into the plane of the figure. The rod moves with speed v = 4.00 m/s in the direction shown. (Figure 1)
Part A
When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge?
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Part B
In what direction does the electric field then point?
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Part C
When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?
Express your answer in volts per meter to at least three significant figures.
2.40
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Part D
Which point, a or b, is at higher potential?
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Some work must have been done in order to create this potential difference, i.e., to separate the charges in the rod. This work was done by the initial force required to pull the rod in opposition to the force on it due to the interaction of the transient current in it with the magnetic field. Note that once the charges are in equilibrium, no force is required to keep the rod moving with constant velocity.
Part E
What is the magnitude Vba of the potential difference between the ends of the rod?
Express your answer in volts to at least three significant figures.
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Part F
What is the magnitude E of the motional emf induced in the rod?
Express your answer in volts to at least three significant figures.
In the figure, a conducting rod with length L = 35.0 cmmoves in a magnetic field B of magnitude 0.360 Tdirected into the plane of the figure. The rod moves with speed v = 4.00 m/s in the direction shown. (Figure 1)
Part A
When the charges in the rod are in equilibrium, which point, a or b, has an excess of positive charge?
a bSubmitHintsMy AnswersGive UpReview Part
Correct
Part B
In what direction does the electric field then point?
from a toward b from b toward aSubmitHintsMy AnswersGive UpReview Part
Correct
Part C
When the charges in the rod are in equilibrium, what is the magnitude E of the electric field within the rod?
Express your answer in volts per meter to at least three significant figures.
E=2.40
V/mSubmitHintsMy AnswersGive UpReview Part
Incorrect; Try Again; 5 attempts remaining
Part D
Which point, a or b, is at higher potential?
a bSubmitHintsMy AnswersGive UpReview Part
Correct
Some work must have been done in order to create this potential difference, i.e., to separate the charges in the rod. This work was done by the initial force required to pull the rod in opposition to the force on it due to the interaction of the transient current in it with the magnetic field. Note that once the charges are in equilibrium, no force is required to keep the rod moving with constant velocity.
Part E
What is the magnitude Vba of the potential difference between the ends of the rod?
Express your answer in volts to at least three significant figures.
Vba= VSubmitHintsMy AnswersGive UpReview Part
Part F
What is the magnitude E of the motional emf induced in the rod?
Express your answer in volts to at least three significant figures.
E= b V ×xb× × XII× × ×L ××a× ×Explanation / Answer
A) b is positive
B) from b toward a
C) in the equilibrium, Fe = FB
q*E = q*v*B
E = v*B
= 4*0.36
= 1.44 N/C
D) b
E) Vba = E*L
= 1.44*0.35
= 0.504 V
F) motional emf = B*v*L
= 0.36*4*0.35
= 0.504 V
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