ngEngineering MasteringComputerskience 12. Ch18 Mamemmmmor system of partides Go
ID: 1563869 • Letter: N
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ngEngineering MasteringComputerskience 12. Ch18 Mamemmmmor system of partides Google Chrome secure l https//session.masteringengineering.com/myct/itemview?assignmentProblemID-5609383&offset; next signed in as Ahmed Problem 18.11 previous 4 of 10 roblem 18.11 Part A The moment of inertia of the astronaut and If he is initially not rotating, and at t 0 he activates the maneuvenng unit about the axis through their center thruster until ho is rotating at 15 per second. through how of mass perpendicular to the page is 40 kg m many degrees has he rotated at t 10 s? A thruster can exert a force T 10 N For safety the control system of his maneuvering unit will not allow his angular velocity to exceed 15 per second Figure 1 or 1 Submit ContinueExplanation / Answer
I= 40 kg.m^, T = 10 N, d = 300 mm
w = 15 degrees/s , t =10s
torque = Td = I*alpha
10*0.3 = 40*alpha
alpha =0.075 rad/s^2
w = alpha*t
(15)(3.14/180) = 0.075*t
t = 3.49 s
theta1 = 0.5*alpha*t^2
= 0.6*(0.075)(3.49)^2
theta1 = 0.457 rad
After this time, the astronauts turns at the fixed rate. He rotated an additional angle given by
theta2 = wt = (15)(3.14/180)(10-3.49)
= 1.704 rad
The total rotation is then
theta = theta1+theta2
= (0.457 +1.704)(180/3.14) = 124 degrees
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