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C a Secure l https//wwwwebassignnet/webwStudent/Assignment-Responseswast?depa16023724 A cue ball (mass o.17s kg) is at rest on a frictionless pool table. The ball is hit dead center by a pool stick, which applies an impulse of +1.25 N s to the ball. The ball then slides along the table and makes an elastic head-on collision with a second ball of equal mass that is initially at rest. Rnd the velocity of the second ball just after it is struck. two partides are moving along the x axis. Particle 1 has a mass mi and a velocity Vi +4.8 m/s. My Notes center of mass of these two partides Partide 2 has a mass m2 and a velocity v2 5,5 m/s. The velocity of the the masses of the is zero. In other words, the center of mass of the partides remains stationary, even though each particle is moving. Find the ratio m1/m of particles. O-1 points cu10 Pas Two stars in a binary system orbit around their center of mass. The centers of the B My Notes o Ask Your Teacher its center is 2.30 x 10" m from the two stars are 7,00 x 1012 m apart. The la of the two stars has a mass of 3.5o x 1030 kg, and system's center of mass. What is the mass of the smaller st 1t pounts Previous Answers cJ107 P 053 O Type to search RMy Notes Ask Your Teacher 219 PM A 40 4/25/2017

Explanation / Answer

12)

impulse= F*t= change in momentum

1.25 N.s = mv

v = 1.25/0.175 = 7.142 m/s

using conservation of momentum

m1u1 +m2u2 = M1v1 + m2v2

1.25 + 0 = .175v1 + .175v2

7.142 = v1 + v2

collison is elastic so

1/2 (.175) (7.142)^2 = 1/2(.175)v1^2 + 1/2(.175)v2^2 or

v1 = 0 , V2 = 7.142 m/s

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