A 140-keV photon strikes an electron and scatters through an angle of 120° from

Question

A 140-keV photon strikes an electron and scatters through an angle of 120° from its original direction. What is the photon wavelength after scattering?

How do you determine that D is the correct answer?

50 A 140-keV photon strikes an electron and scatters through an angle of 120 from its original direction. What is the photon wavelength after scattering? (melectron x 10-31 kg, c 3.00 x 108 m/s, h 36.626 x 10-34 J. s) A) 9.50 x 10-12 m B) 10.50 x 10-12 m CO 11.50 x 10-12 m D) 12.50 x 10-12 m E) 13.50 x 10-12 m

Explanation / Answer

Using Compton scattering equation:

lambda1 - lambda = (h/m*c)*(1 - cos A)

lambda = wavelength before scattering

Ei = hc/lambda

lambda = 6.625*10^-34*3*10^8/(140*10^3*1.6*10^-19) = 8.87*10^-12 m

So,

lambda1 = 8.87*10^-12 + (6.625*10^-34/(9.1*10^-31*3*10^8))*(1 - cos 120 deg)

lambda1 = 12.51*10^-12 m

Correct option is D.

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