MA HW 10 (25) g C O www.webassign. t/web/Student/Assignment-Responses/submit?dep
ID: 1564824 • Letter: M
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MA HW 10 (25) g C O www.webassign. t/web/Student/Assignment-Responses/submit?dep 15409778 -13.33 points SerPoP5 25. P.029.M My Notes Ask Your Teacher A triangular glass prism with apex angle of 60.0 has an index of refraction n 1.42 see figure below). What is the smallest angle of incidence 81 for which a light ray can emerge from the other side? Need Help? Read t L t Master -13.33 points SerPoP5 25-P035 My Notes Ask Your Teacher Assume a transparent rod of diameter d 3.24 Hm has an index of refraction of 1.35. Determine the maximum angle for which the light rays incident on the end of the rod in the figure below are subject to total internal reflection along the walls of the rod. Your answer defines the size of the cone of acceptance for the rod 9 AM ENG 4/26/2017Explanation / Answer
3) sinc = 1/1.42
c = 44.77°
Solve using geometry
90 – 44.77 = 45.23
180 – 60 – 45.23 = 74.77
90 – 74.77 = 15.23 = 2
Use Snell’s law
1 sin1 = 1.42 sin15.23
1 = 21.90
4) Critical angle is sin^–1 (1/µ) = sin^–1 (1/1.35) = 47.79
Angle of refraction that will make the ray strike at the critical angle is 90 – 47.79 = 42.21
sin i = 1.35 sin 42.21
i = 65.08
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