A 4.0 mu F and a 6.0 mu F capacitor are connected in series across an 8.0 V DC s
ID: 1565432 • Letter: A
Question
A 4.0 mu F and a 6.0 mu F capacitor are connected in series across an 8.0 V DC source. What is the charge on the 4.0 mu F capacitor? 19 mu C 25 mu C 40 mu C 20 mu C 12 mu C A system of capacitors is connected across a 90 V DC voltage source as shown in Fig 16 6. What is the equivalent capacitance of this system? 15 mu F 1.5 mu F 3.6 mu F 3.3 mu F None of the other answers is correct An electron moving perpendicular to a magnetic field of 22 times 10^-2 T moves in a circle of certain radius. If the electron is moving with a speed of 15 times 10^7 m/s, what is the radius of the circle? 3.9 times 10^-4 m 1.5 times 10^-3 m 2.2 times 10^-3 m 3.9 times 10^-3 m Rayleigh scattering would have 400 nm light be scattered how many times as much as 800. nm light? 4 2 8 32 16 Two coins carry identical charges. These two coins are lying 2.00 m apart on a table. If each of these coins experiences a force of 2.00N, how large is the charge on each coin? 29.8 mu C 6.67 mu C 1.49 mu C 14.9 mu C 2.98 mu CExplanation / Answer
27.
We know that, In series connection charge in each capacitance is equal to the total charge.
1/Ceq = 1/C1 + 1/C2
Ceq = 4*6/(4 + 6)
Ceq = 2.4 uF
V = 8.0
Q = Ceq*V = 2.4*8 = 19.2 uC
Charge on 4uF capacitor = 19.2 uC
Correct option is A.
28.
In series:
1/Ceq = 1/C1 + 1/C2
In upper brance
Cs1 = 2*4/(2+4) = 4/3 uF
in lower branch
Cs2 = 3*6/(3+6) = 2 uF
In parallel
Ceq = C1 + C2, So
Ceq = 2 + 4/3 = 10/3 uF = 3.33 uF
Correct option is D.
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