In the figure, a cube of edge length L = 0.304 m and mass 1060 kg is suspended b

Question

In the figure, a cube of edge length L = 0.304 m and mass 1060 kg is suspended by a rope in an open tank of liquid of density 1.04E+3 kg/m^3. Find (a) the magnitude of the total downward force on the top of the cube from the liquid and the atmosphere, assuming atmospheric pressure is 1.00 atm, (b) the magnitude of the total upward force on the bottom of the cube, and (c) the tension in the rope. (d) Calculate the magnitude of the buoyant force on the cube using Archimede's principle. (a) Number 25891.84 Units T N (b) Number 56875.52. Units T N (c) Number 675.04123 (d) Number 2863.3877

Explanation / Answer

Sol

Force on top of cube F1 = pXA = (10^5 + 1040X10X0.304/2)X0.304X0.304 = 9387 newton

Total upward force F2 = PXA = ( 10^5 + 1040X10X.304X3/2)X0.304X.304 = 9679.8 N

Let the tension be T, so balancing force

T + F2 - F1 -W = 0

T = W+F1-F2 = 10600 -9679.8 + 9387 = 10307 N

Buyonce force = VXdensity X gravity = L3X1040X10 = 292.8 N

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