question #2 please Calculate the binding energy (in MeV) and the binding energy

Question

question #2 please

Calculate the binding energy (in MeV) and the binding energy per nucleon of Potassium-39. [See appendix B for the relevant information]. For each type of decay state the resulting daughter nucleus: a) The proton emission of Bismuth-185 b) The beta decay of Calcium-51 c) The electron capture of Fermium-250 d) The alpha decay of Xenon-110 The activity of a sample of radioactive silver-108 is 6.4 times 10^4 decays/s. Exactly 12 minutes later the activity of the sample is measured to be 2.0 times 10^3 decays/s. Use this information to calculate the half-life of Silver-108. The triple-alpha fusion process that occurs in the centers of some stars creates Carbon-12 nuclei by essentially fusing together three Helium-4 nuclei. Calculate the Q-value for this process in MeV. A beam of nuclei (with RBE = 16) is used for cancer therapy. Each nucleus in the beam has an energy of 125 MeV. The beam is focused on a 0.15 kg tumor which receives a biologically effective dose of 175 rem.

Explanation / Answer

2.a)

A proton emission leaves the parent nucleus with the mass number and number of protons both reduced by 1

So resulting daughter nucleus is Lead-184.

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2.b)

Beta decays are of two types: = - decay and + decay.

In case of - decay, the mass number of the parent nucleus remians the same but atomic number increases by 1.

So if - decay takes place daughter nucleus will be Scandium-51

In case of + decay, the mass number of the parent nucleus remians the same but atomic number decreases by 1.

So if + decay takes place daughter nucleus will be Potassium-51

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2.c)

In case of electron capture, the mass number of the parent nucleus remains the same but atomic number decreases by 1.

So daughter nucleus will be Einsteinium-250

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2.d) In alpha decay the parent nucleus lose mass number by 4 and atomic number by 2.

So the daughter nucleus will be Tellurium-106.

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This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification or correction, feel free to ask.....

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