The mass of the book is mB = 0.5 kg and the mass of the cinderblock is mC = 8 kg
ID: 1566607 • Letter: T
Question
The mass of the book is mB = 0.5 kg and the mass of the cinderblock is mC = 8 kg. The coefficient of static friction between the cinderblock and the table is s = 0.7 and the coefficient of kinetic friction between the cinderblock and the book is k = 0.5. Note: The cinderblock remains at rest on the table.What is the magnitude of the friction force between the cinderblock and the table? The mass of the book is mB = 0.5 kg and the mass of the cinderblock is mC = 8 kg. The coefficient of static friction between the cinderblock and the table is s = 0.7 and the coefficient of kinetic friction between the cinderblock and the book is k = 0.5. Note: The cinderblock remains at rest on the table.
What is the magnitude of the friction force between the cinderblock and the table? Book Cinder block Table
Explanation / Answer
IN vertical,
N - (mB + mC)g = 0
N = 8.5g
f_max = us N = 0.7 x 8.5 x 9.8 = 58.31 N
for Book.
N = 0.5g
fk = uk N = 0.5 x 0.5 x 9.8 = 2.45 N
and 2.45 < f_max
so friction force on Cinderblock will be 2.45 N ......Ans
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