The expected answer(s) is in red. If possible, please show all of the steps whil

Question

The expected answer(s) is in red. If possible, please show all of the steps while solving this problem. I've had much difficulty with these problems. Please and thank you.

A bathysphere is a spherical submarine that can descend in seawater. A bathysphere has a radius of 1.50 m and a mass of 1.20 x 104 kg. To descend, it must take on mass in the form of seawater. What mass of seawater must enter the bathysphere so it descends at a constant speed of 1.20 m/s when there is an upward drag force of 1,100 N on it? 2,670 kg What is the buoyant force on the bathysphere? 1.43 x 105 N What weight of water does the bathysphere displace? 1.43 x 105 N The density of seawater is 1.03 x 10 k/gm Assume the bathysphere starts completely submerged before descending

Explanation / Answer

Upthrust force = pgV

p =1030 kg/m^3, r =

F =1100 N

Since the vessel is moving at a constant speed, the resultant force on it should equal zero.

downward acting forces = upward acting forces

M*g = pgV + F

M*9.8 = 1030*9.8*(4/3)3.14*1.5^3 + 1100

M =1.470*10^4 kg

M is the mass of the vessel in addition to the water it has taken in.

mass of water m = M - mass of vessel

m = 1.466*10^4 -1.2*10^4

m = 2670 kg

Buoyant force = pvg

= 1030*9.8*(4/3)3.14*1.5^3

= 1.43*10^5 N

Buoyant force = weight of displaced water

weight of displaced water = 1.43*10^5 N

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