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Density Of a solid , using water Equation 8.7 P obj =P w W/ W-W app,w Testing Ar

ID: 1567725 • Letter: D

Question

Density Of a solid , using water Equation 8.7 Pobj=Pw W/ W-Wapp,w

Testing Archimedes' Law Calculating the density of a solid object and ethanol Calculating the density of a floating object 1. Calculate the weight of the water displaced by the immersed object, W_bf - W_bp using the data from Part A. 2. Calculate the apparent loss of weight of the object when completely immersed in water, W - W_app, W, using the data from Part A. 3. Archimedes' Law predicts that the weight of the displaced water equals the apparent loss of weight of the object. Do your results support Archimedes' Law? 4. Calculate the density of the object rho_obj using equation 8.7 and the data from Pan B. 5. Calculate the % error in your result for rho_obj. 6. Calculate the density of the ethanol rho_E using equation 8.8 and the data from Pan B. 7. Calculate the % error in your result for rho_E.

Explanation / Answer

1. Weight of water displaced by the immersed object = Wb,f - Wb,i

= 145.9-137 = 8.9 g

2. Apparent loss of weight of object when fully immersed in water = W-Wapp,w

= 39-24.5 = 14.5 g

3. According to Archimedes' Principle,

Wb,f -Wb,i = W-Wapp,w

But above results doesn't supports this principle.

4. Density of solid,

Pobj = PwW / W-Wapp,w

Density of water, Pw = 1 g/cm^3

So, Pobj = 1*39/39-24.5 = 2.689 g/cm^3

5. Percentage error,

Density of floating oject from given data = mass / Volume = 200 / (30.6-21.9)*3.5*2.7 = 2.433 g/cm^3

So, Error % = (2.433-2.689/2.433)*100 = -10.52%

6. Density of Ethanol,

PE = PwW-Wapp,E/W-Wapp,w

= 1*(39-27.5)/(39-24.5) = 0.793 g/cm^3

7. Density of Ethanol in air = 0.789 g/cm^3

So, Error % = (0.789-0.793 / 0.789)*100 = -0.51%

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