The circuit below consists of 3 identical light bulbs (A, B, C) two identical in

Question

The circuit below consists of 3 identical light bulbs (A, B, C) two identical inductors, and two identical capacitors. At very high frequencies, which light bulbs will be lit up? Circle one. (a) Bulbs A and B (b) Bulbs A and C (c) Bulbs B and C d) Bulbs A, B, and C (e) No bulbs will be lit A typical red laser pointer has a wavelength of 632 nm and 632nm and converts 3mw of power into light. Estimate the number of photons emitted by this laser pointer in one second. Circle one. (a) 10^10photons (b) 10^13 photons (c) 10^16 photons (d) 10^19 photons (e) 10^22 photons In the circuit below, a conducting bar is moved to the right at a constant velocity in a uniform magnetic field that points into the page. Which of the following statements is true about the induced EMF and the current in the resistors? Circle one. (a) Epsilon_100 > Epsilon_200, I_100 > I_200 (b) Epsilon_100

Explanation / Answer

G)

Reactance offered by inductor is XL = L, so at very high frequency the current flow thorugh indictor will be negligible due to high reactance as XL is directly prportional to .

Reactance offered by capacitor is Xc = 1/C, so at very high frequency the current flow thorugh capacitor will be high due to low reactance as XL is inversely prportional to .

So, in the given circuit current through bulb A will be zero at very high frequency as it is connected in series with the upper inductor. Bulbs B and C will glow at high frequency as, they are not in series with any of the inductors.

At very high frequency the current will follow the path from the poer source through the lower capacitor to bulb B to upper capacitor to bulb C and then back to the power source.

So, the correct option is (c)

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(H)

Energy of a single photon of the laser is;

E = hc/ = (6.63X10-34 J.s)(3X108m/s)/632X10-9m

or, E = 3.15X10-19 J

Power used is 3 mW, so energy used in 1 second is 3 mJ, so number of photons emitted in one second is;

n = 3X10-3J/(3.15X10-19 J)

or, n = 0.95X1016

So, the correct option is c)

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(I)

On the left side of the bar area of the loop is increasing and on right side area of the loop is decreasing. But the rate is same on both saides. So, magnitude of rate of change of flux will be same and so the emf induced will be same. But the current in 200 resistor will be less due to higher resistance.

So correct option is d)

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This concludes the answers. Check the answer and let me know if it's correct. If you need any more clarification or correction, feel free to ask.....

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