A potter\'s wheel moves uniformly from rest to an angular speed of 0.19 rev/s in

Question

A potter's wheel moves uniformly from rest to an angular speed of 0.19 rev/s in 25.0 s.

(a) Find its angular acceleration in radians per second per second.
________ rad/s2

(b) Would doubling the angular acceleration during the given period have doubled final angular speed?

________ YesNo

:

:

A dentist's drill starts from rest. After 3.70 s of constant angular acceleration it turns at a rate of 2.75 104 rev/min.

(a) Find the drill's angular acceleration.
______ rad/s2

(b) Determine the angle (in radians) through which the drill rotates during this period.
______ rad

Explanation / Answer

part 1 )

wf = wi + alpha*t

wi = 0 rad/s

wf = 0.19 rev/s = 1.1938 rad/s

t = 25 s

alpha = (wf- wi)/t = 0.0478 rad/s^2

part b )

Yes

for doubling the angular acceleration

2*alpha = 2*(wf -wi)/t

the angular speed is double as well

part 2 )

alpha = (wf-wi)/t

wf = 2.75 x 10^4 rev/min = 2879.79 rad/s

t = 3.7 s

alpha = 778.32 rad/s^2

part b )

theta = (wf + wi )*t /2

theta = 5327.62 rad

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