A student launches a rocket which starts from rest and from ground small level (

Question

A student launches a rocket which starts from rest and from ground small level (a height of h = 0). At a height of h = 1.1 km the rocket reached a velocity a of v_f = 259 m/s. At that height the rocket runs out of fuel and therefore there is no longer any thrust propelling the rocket. You may assume that the positive direction is upwards in this problem. What was the rocket's acceleration a_f (m m/s^2), during this period from when it is launched to the point that runs out of fuel? Assume constant acceleration Numeric: A numeric value is expected and not expression. After the rocket engine turns of a height of h = 1.1 km, continues to move upward based on the velocity that it reached. What is the rocker's acceleration during this period (after the engine shuts off but before the rocket returns to the ground), a_2 (m m/s^2)? A numeric value is expected and not an expression. What is the numeric value of the total height reached by the rocket in meters, as measured from the ground at h = 0? A numeric value is expected and not an expression.

Explanation / Answer

h=1.1 km

Vf=259 m/s

A) a = (v^2/2h)

= (259^2/2*1100)

= 30.49 m/sec^2

B) a = -g = -9.8 m/sec^2

C) Hmax = Hf + vf^2/(2g)

= 1100 + 259^2/(2g)

= 1100+3422.5

= 4522.5m

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