Two positive point charges each 12 uC lie along the x axis at x=-.1m and x=+.1m.

Question

Two positive point charges each 12 uC lie along the x axis at x=-.1m and x=+.1m. Find the electric field at the origin (0,0). Find the electric field at point (0,.25m) on the y axis. Two positive point charges each 12 uC lie along the x axis at x=-.1m and x=+.1m. Find the electric field at the origin (0,0). Find the electric field at point (0,.25m) on the y axis. Two positive point charges each 12 uC lie along the x axis at x=-.1m and x=+.1m. Find the electric field at the origin (0,0). Find the electric field at point (0,.25m) on the y axis.

Explanation / Answer

at(0,0) EF due to both the charges will be equal and opposite in direction

so net EF at (0,0) will be 0

EF at(0 ,0.25)

EF due to both the charges = kq/r^2 = 9*10^9*12*10^-6 / (1^2 + 0.25^2)

= 101647.06 N/C

Net EF = 2*101647*0.25/1 = 50823.53 N/C

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