A sinusoidal electromagnetic wave of frequency 6.10×1014Hz travels in vacuum in

Question

A sinusoidal electromagnetic wave of frequency 6.10×1014Hz travels in vacuum in the +x direction. The magnetic field is parallel to the y axis and has amplitude 5.80×104T.

Part A

Find the magnitude of the electric field.

Express your answer to three significant figures with the appropriate units.

Part B

Find the direction of the electric field.

Find the direction of the electric field.

parallel to the + y-axis

Part C

Choose the wave functions for the electric and magnetic fields in the form of E=Emaxsin(tkx), B=Bmaxsin(tkx).

Choose the wave functions for the electric and magnetic fields in the form of , .

parallel to the + x-axis parallel to the y-axis parallel to the + z-axis parallel to the x-axis parallel to the z-axis

parallel to the + y-axis

Part C

Choose the wave functions for the electric and magnetic fields in the form of E=Emaxsin(tkx), B=Bmaxsin(tkx).

Choose the wave functions for the electric and magnetic fields in the form of , .

E=(1.74×105V/m)sin((3.83×1015rad/s)t+(1.28×107rad/m)x). B=(5.80×104T)sin((3.83×1015rad/s)t+(1.28×107rad/m)x). E=(1.74×105V/m)sin((3.83×1015rad/s)t(1.28×107rad/m)x). B=(5.80×104T)sin((3.83×1015rad/s)t(1.28×107rad/m)x). E=(1.74×105V/m)sin((3.83×1015rad/s)t(1.28×107rad/m)x). B=(5.80×104T)sin((3.83×1015rad/s)t(1.28×107rad/m)x). E=(1.74×105V/m)sin((3.83×1015rad/s)t+(1.28×107rad/m)x). B=(5.80×104T)sin((3.83×1015rad/s)t+(1.28×107rad/m)x).

Explanation / Answer

a) E=B*c= 5.8*10^-4*3*10^8 = 17.4*10^4 V/m= 1.74*10^5 V/m

b) Negative Z axix ( Because E*B points towards Velocity )

So E*j=i ( E must be -k)

c) Option B

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